# Python Set difference() Method

The `set.difference()` method returns the new set with the unique elements that are not in the other set passed as a parameter.

### Syntax:

``set.difference(*other_set)``

#### Parameters:

other_set: (Required) One or more sets separated by a comma.

#### Return Value:

Returns a new set.

The following example demonstrates the `set.difference()` method.

Example: difference()
``````nums1 = {1, 2, 2, 3, 4, 5}
nums2 = {4, 5, 6, 7, 8, 8}

nums3 = nums1.difference(nums2)
nums4 = nums2.difference(nums1)

print("nums1 - nums2: ", nums3)
print("nums2 - nums1: ", nums4)
``````
Output
``````nums1 - nums2: {1, 2, 3}
nums2 - nums1: {8, 6, 7}
``````

The following finds the differences between the two string sets.

Example: difference()
``````cities = {'Bangalore','Mumbai','New York','Honk Kong','Chicago'}
indianCities = {'Bangalore','Mumbai'}
nonindiancities = cities.difference(indianCities)
print("Non-Indian Cities: ", nonindiancities)
``````
Output
``````Non-Indian Cities:  {'Honk Kong', 'Chicago', 'New York'}
``````

## Passing Multiple Sets

You can also specify multiple sets in the `difference()` method, as shown below.

Example: Multiple Parameters
``````nums1 = {1, 2, 2, 3, 4, 5}
nums2 = {4, 5, 6, 7, 8, 8}
nums3 = { 3, 5, 8, 9, 10}

diff = nums1.difference(nums2, nums3)

print(diff)
``````
Output
``````{1, 2}
``````

## Using the - Operator

The `-` operator can also be used for calculating the difference of two sets.

Example: - Operator
``````nums1 = {1, 2, 2, 3, 4, 5}
nums2 = {4, 5, 6, 7, 8, 8}
nums3 = { 3, 5, 8, 9, 10}

diff = nums1 - nums2 - nums3
print('Numbers Differences: ', diff)

cities = {'Bangalore','Mumbai','New York','Honk Kong','Chicago'}
indianCities = {'Bangalore','Mumbai'}
nonindiancities = cities - indianCities
print("Non-Indian Cities: ", nonindiancities)
``````
Output
``````Numbers Differences: {1, 2}
Non-Indian Cities: {'Honk Kong', 'Chicago', 'New York'}
``````
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